1 | // RUN: %clang_cc1 -verify -std=c++11 %s |
2 | |
3 | using T = int[]; |
4 | |
5 | void f() { |
6 | int *p = &(int&)(int&&)0; // expected-warning {{temporary whose address is used as value of local variable 'p' will be destroyed at the end of the full-expression}} |
7 | |
8 | int *q = (int *const &)T{1, 2, 3}; // expected-warning {{temporary whose address is used as value of local variable 'q' will be destroyed at the end of the full-expression}} |
9 | |
10 | // FIXME: We don't warn here because the 'int*' temporary is not const, but |
11 | // it also can't have actually changed since it was created, so we could |
12 | // still warn. |
13 | int *r = (int *&&)T{1, 2, 3}; |
14 | |
15 | // FIXME: The wording of this warning is not quite right. There are two |
16 | // temporaries here: an 'int* const' temporary that points to the array, and |
17 | // is lifetime-extended, and an array temporary that the pointer temporary |
18 | // points to, which doesn't live long enough. |
19 | int *const &s = (int *const &)T{1, 2, 3}; // expected-warning {{temporary bound to local reference 's' will be destroyed at the end of the full-expression}} |
20 | } |
21 | |
22 | // PR38355 |
23 | void g() { |
24 | const int a[] = {a[0]}; |
25 | const int b[] = {a[0]}; |
26 | } |
27 | |